In fig. if ⎳abc 20° then ⎳aoc is equal to
WebFeb 19, 2024 · Best answer Given: ∠OBD = 50° Here, AB and CD are the diameters of the circles with centre O. ∠DBC = 90° …. (i) [Angle in the semi-circle] Also, ∠DBC = 50° + ∠OBC 90° = 50° + ∠OBC or ∠OBC = 40° Again, By degree measure theorem: ∠AOC = 2 ∠ABC ∠AOC = 2∠OBC = 2 x 40° = 80° ← Prev Question Next Question → Find MCQs & Mock Test JEE … WebApr 7, 2024 · $ \Rightarrow 45^\circ + \angle AOC = 180^\circ $ Solving further, $ \Rightarrow \angle AOC = 180^\circ - 45^\circ = 135^\circ $ Therefore, the required value of $\angle AOC = 135^\circ $ Note: A triangle is a 3-sides polygon having 3 sides, 3 angles and 3 vertices. Also, the sum of any two sides of a triangle is always greater than the third side.
In fig. if ⎳abc 20° then ⎳aoc is equal to
Did you know?
WebIn Fig. 10.6, if ∠OAB = 40º, then ∠ACB is equal to : a. 50º b. 40º c. 60º d. 70° Solution: In triangle OAB OA = OB ( radius of a circle) ∠OAB = ∠OBA ∠OBA = 40º (angles opposite to … http://thegreat9a.weebly.com/uploads/1/0/5/9/10595316/1_4_1_1_4.pdf
WebIn the given figure, if ∠ABC = 20∘ , then ∠AOC is equal to ____________. Solution Given: ∠ABC = 20° ... (1) We know, the angle subtended by an arc at the centre is twice the angle … WebAug 19, 2024 · ∠ABC = 20° We know that, “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle” According to the …
WebSolution Given, ∠OAB=30∘ and ∠OCB= 57∘ In ΔAOB, AO = OB [both are the radius of the same circle] ⇒ ∠OBA= ∠BAO=30∘ [angles opposite to equal sides are equal] ⇒ ∠AOB+∠OBA+∠BAO=180∘ [by angle sum property of a triangle] ∴ ∠AOB+30∘+30∘ =180∘ ∴ ∠AOB= 180∘−2(30∘) ∠AOB=180∘−60∘ = 120∘ ........... (i) Now, in ΔOCB, OC = OB [both are … Web∠AOC = 2 × ∠ABC = 2 × 20° = 40° Therefore, ∠AOC = 40° Hence, option B is the correct answer. 5. In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠ CAB is equal …
WebIn the given figure, if ∠ ABC = 45°, then ∠ AOC = Options 45° 60° 75° 90° Advertisement Remove all ads Solution 90° We have to find ∠AOC. As we know that the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle. ∠ A O C = 2 ∠ A B C = 2 × 45 = 90°
WebNov 19, 2024 · In a given figure , O is centre of circle if angle ABC = 20 degree then angle AOC is equal to : (i) 20 degree (ii) 40 degree (iii) 60 degree (iv) 10 degree See answers Advertisement Advertisement aftabansari48 aftabansari48 ... Advertisement svsatardekar73 svsatardekar73 Answer: Step-by-step explanation: GIVEN:ABC=20. So, angle AOC=2×ABC ... people running for governor in oregon 2022people running for congress in paWebWe know that angle subtended by an arc at the center of circle in double the angle subtended at the remaining part. ∠AOC=2∠ABC. ∠AOC=2×20 0. ∠AOC=40 0. toggle switch ignition push button startWebIn Fig.10.4, if ∠ABC = 20º, then ∠AOC is equal to: a. 20º b. 40º c. 60º d. 10º Solution: We know that Angle at the centre of the circle is twice the angle at the circumference … toggle switch html formWebIn Fig. 10.6, if ∠OAB = 40º, then ∠ACB is equal to : a. 50º b. 40º c. 60º d. 70° Solution: In triangle OAB OA = OB ( radius of a circle) ∠OAB = ∠OBA ∠OBA = 40º (angles opposite to equal sides are equal) Using the angle sum property ∠AOB + ∠OBA + ∠BAO = 180º Substituting the values ∠AOB + 40º + 40º = 180º By further calculation ∠AOB + 80º = 180º people running for congress in georgiaWeb∠ABC = 20° We know that, “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle” According to the theorem, we have, ∠AOC = 2 × ∠ABC = 2 × 20° = 40° Therefore, ∠AOC = 40° Hence, option B is the correct answer. Video transcript people running for governor of marylandWebAccording to the question, ∠ABC = 20°. We know that, “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle”. … toggle switch identification