If sum of 2 numbers is 1215 and hcf is 81
Web29 jul. 2024 · It is given that the sum of two numbers is = 1215 And H.C.F is = 81 Let's assume two numbers be x and y. As HCF of both numbers is 81 so both will be a multiple of 81 So First number is = 81x Second number is = 81y Now, 81x + 81y = 1215 ............ Web3 jun. 2012 · Expert Answer It is given that the sum of two numbers is 1215 and their H.C.F is 81 Since the H.C.F of two numbers is 81, the two numbers are 81x and 81y. Now, 81x + 81y = 1215 [Sum of two numbers is 1215] or, 81 (x + y) = 1215 or, (x + y) = 15 Such …
If sum of 2 numbers is 1215 and hcf is 81
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WebSolution Let, the two numbers be a and b. Let the value of a be 161. Given: HCF = 23 and LCM = 1449 we know, a x b = HCF x LCM ⇒⇒ 161 x b = 23 x 1449 ⇒⇒ Therefore, b = Hence, the other number b is 207 Suggest Corrections 28 Similar questions Q. The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other. Q. Web22 mrt. 2024 · Question 24 If 217𝑥 + 131𝑦 = 913, 131𝑥 + 217𝑦 = 827, then 𝑥 + 𝑦 is (a) 5 (b) 6 (c) 7 (d) 8Given equations 217𝑥 + 131𝑦 = 913 …(1) 131𝑥 ...
Web22 mrt. 2024 · Transcript. Question 1 The ratio of LCM and HCF of the least composite and the least prime numbers is (a) 1 : 2 (b) 2 : 1 (c) 1 : 1 (d) 1 : 3 Now, Least composite number = 4 Least prime number = 2 LCM of 4 and 2 = 4 HCF of 4 and 2 = 2 Thus, Ratio of LCM … WebThe sum of two numbers is 1215 and their HCF is 81. If the numbers are between 500 and 700, then the sum of the reciprocals of the number is _____. a + b = 1
WebIf sum of two numbers is 1215 and their HCF is 81, then the possible number of pairs of such numbers are _____. If sum of two numbers is 1215 and their HCF is 81, then the possible number of pairs of such numbers are 4. Explanation:-Since HCF = 81, two … WebGiven : sum of two numbers=256 HCF=32 SOLUTION: If HCF =32 then two numbers can be taken as , 32*x & 32*y , where x&y are co prime (to make sure HCF is 32) Now since sum is 256, So, 32* (x+y)=256 X+y=256/32=8 x+y =8 and x&y are co prime. So following are the possibilities exists for x&y are: x,y ; 32*x , 32*y 1,7 ; 32*1 , 32*7 =32,224
Web22 mrt. 2024 · Correct option : (c) 4. Since, HCF of both number is 81. ∴ ∴ Both numbers are multiple of 81. Let numbers are 81a & 81b when a & b are coprimes. ⇒ a + b = 1215 81 = 15. ⇒ a + b = 1215 81 = 15. Possible pair of a & b are (1,14), (2,13), (4,11) & (7,8). ∴ ∴ …
WebQuestion : If the sum of two numbers is 1215 and their HCF is 81, then the possible number of pairs of such numbers are a) 2 b) 3 c) 4 d) 5 Doubt by Vanshika Solution : HCF of both the numbers is 81, it means that both are divisible by 81 or we can also say that both are the multiples of 81. Correct? Let us consider the two numbers by P and Q Now 奇跡のバックホーム あらすじWebAnswer (1 of 2): If the numbers are m and n, put m = 15m’ and n = 15n’. Then 15(m’+n’) = m+n = 150. Hence m'+n' = 10 and gcd(m', n') = 10. Since all the given ... 奄美 海水浴 おすすめWebThe LCM of two numbers is 28 times their HCF. The sum of their LCM and HCF is 1740. If one of the numbers is 240, find the other number. (a) 275. (b) 425. (c) 420. (d) 540. View Answer. Ques. Find the least number which when divided by 16, 18 and 20 leaves a remainder 4 in each case, but is completely divisible by 7. bsプレミアム 顔WebSolution The correct option is C 500 HCF of two numbers is always a factor of LCM of those two numbers. In the given options, 1200 is not divisible by 500. So, 500 cannot be the HCF of the two numbers whose LCM is 1200. Suggest Corrections 131 Similar questions Q. The LCM of two numbers is 1200. Which of the following cannot be their HCF? (a) 600 bsホーム 不動産WebQuestion 21 If sum of two numbers is 1215 and their HCF is 81, then the possible number of pairs of such numbers are (a) 2 (b) 3 (c) 4 (d) 5 Since HCF of both numbers is 81 It means 81 is a factor of both numbers Thus, let us assume numbers are 81x and 81y … 奄美高校 ポスターWeb14 dec. 2024 · Solution For If sum of two numbers is 1215 and their HCF is 81 then the possible numbers of pairs of such numbers is- A) 2 B) 3 C) 4 D) 5 奄美高校 ホームページWebSelect ItemCode & Click here use existing Item Code: New Item Code: Item Name: Unit: None 1 BOOK 1 LOT 1 LOT (1 X 500 PCS) 10 CARTS/BOX 10 LTRS 10/CTN 100/GM 100/PKT 100/PKT 1000K bs ブロックノイズ 原因