WebFeb 14, 2024 · Kusto Query Language provides IndexOf function (searches the first occurrence). The question is how to find the last occurrence of some substring. azure-application-insights kql Share Improve this question Follow asked Feb 14, 2024 at 2:14 ZakiMa 5,367 1 22 48 Add a comment 2 Answers Sorted by: 6 WebJan 10, 2024 · Replacing/Removing value for a given key in a dynamic value in Kusto Ask Question Asked 3 years, 2 months ago Modified 2 years, 3 months ago Viewed 3k times Part of Microsoft Azure Collective 1 Is there any way in Kusto using which we can replace value for a specific key within a dynamic value in Kusto?
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WebMar 6, 2024 · Kusto is built to support tables with a huge number of records (rows) and large amounts of data. To handle such large tables, each table's data is divided into smaller "chunks" called data shards or extents (the two terms are synonymous). The union of all the table's extents holds the table's data. WebApr 11, 2024 · Kusto Sequencing and Summarizing events. I am working on a Splunk to Sentinel migration and I have this scenario where we have File Audit events like 4656, 4663, 4659 with different values for AccessList column and we want to merge 2 events if the AccessList value for the first event is e.g., 1537 and the AccessList value for the next … efjez
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WebMar 27, 2024 · This command runs in the context of a specific database. It moves the specified extents from their source tables to the destination table, and then drops the specified extents from the destination table. All of the drop and move operations are done in a single transaction. Note WebJul 11, 2024 · Microsoft 365 Defender's Advanced Hunting tool uses Kusto as its query language (KQL). Examples of the format of a simple query: SchemaTableName where ColumnName stringoperator "value" In a... WebMay 16, 2024 · The Kusto Query language has an replace function which replaces all regex matches with another string. // Example on replacing strings datatable(Age:string,FirstName:string,LastName:string) [ "50","Stefan","Stranger", "40","John", "Doe", "30","Jane", "Doe", ] extend NewAge=replace(@'50', @'45', Age) … efj khl p ci ihd ugldi